WebMarks 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100 No. of students 5 9 16 22 26 18 11 6 4 3 Draw an ogive for the given distribution on a graph sheet. Use a suitable scale for ogive to estimate the following: (i) the median (ii) the lower quartile (iii) the number […] WebIn a class test, marks obtained by 120 students are given in the following frequency distribution. If it is given that mean is 59, find the missing frequencies x and y. Solution ∑fi = 90+x+y But ∑fi = 120 [Given] ∴ 90+x+y =120 x =120−90−y= 30−y …(i) M ean =A+ ∑fidi ∑fi …
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WebApr 4, 2024 · In a class test, the sum of Gagan’s marks in mathematics and English is $45$. If he had $1$ more mark in Mathematics and $1$ less in English, the product of marks would have been $500$. Find the original marks obtained by Gagan in Mathematics and English separately. Questions & Answers CBSE Mathematics Grade 10 Linear Equations in … WebQuestion: Marks obtained by male students in a class is normally distributed with mean of 65 and standard deviation of 5, while marks obtained by female students is normally distributed with mean of 68 and standard deviation of 14. Which of the following statements is TRUE? a. The peak of the normal curve for female is higher than male. b. The spread of …
WebTo find: Mean of marks obtained by 8 students Marks obtained by 8 students in class test = 12, 14, 16, 18, 20, 10, 11, and19 (given) Total marks obtained by 8 students in class test = … WebTotal marks obtained by 8 students in class test = (12 + 14 + 16 + 18 + 20 + 10 + 11 + 19) = 120 Using the mean formula, Mean = (Sum of Observation) ÷ (Total numbers of Observations) = 120/8 = 15 Therefore, the mean of marks obtained by 8 students is 15.
Web11 rows · The marks obtained by 120 students in a test are given below.MarksNo. of students 0 - 10 5 10 ... WebTo find: Mean of marks obtained by 8 students Marks obtained by 8 students in class test = 12, 14, 16, 18, 20, 10, 11, and 19 (given) Total marks obtained by 8 students in class test = …
WebThe marks obtained by 120 students in a mathematics test is given below: Dr Draw an ogive for the given distributions on a graph sheet. use a suitable scale for your ogive. use your …
WebApr 10, 2024 · By Dylan Scott @dylanlscott Apr 10, 2024, 7:30am EDT. The ADHD drug Adderall is still experiencing a shortage in the US, six months after the FDA first announced the inadequate supply. Getty ... chirbase数据库WebIn a class test, 50 students obtained marks as follows- Find the modal class and the median class. Medium View solution > For the following distribution: The modal class is Medium View solution > View more More From Chapter Statistics View chapter > Revise with Concepts Example Definitions Formulaes Learn with Videos 14 mins Mode of Ungrouped … chirba food truckWebThe marks obtained by 19 students of a class are given below: 27, 36, 22, 31, 25, 26, 33, 24, 37, 32, 29, 28, 36, 35, 27, 26, 32, 35 and 28. Find: Median Lower quartile Upper quartile Inter-quartile range VIEW SOLUTION Exercise 24 (C) Q 4.1 … graphic designers forumWebMar 30, 2024 · Transcript. Ex 3.1, 6 The marks (out of 100) obtained by a group of students in a science test are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75. Find the: (i) Highest and the lowest marks obtained by the students Arranging data in ascending order 39, 48, 56, 75, 76, 81, 85, 85, 90, 95 Highest marks = 95 Lowest marks = 39 Ex 3.1, 6 The marks (out ... chir battiWebDec 27, 2024 · In a class test, marks obtained by 120 students are given in the following frequency distribution. If it is given that mean is 59, find the missing frequencies x and y and ... It is given that the class has 120 students and is also equal to the sum of frequencies. Therefore 1 + 3 + 7 + 10 + 15 + x + 9 + 27 + 18 + y = 120. graphic designer self branding naWeb01 The marks obtained out of 25 by 20 students of a class in the examination are given below. 19, 9, 14, 15, 22, 10, 20, 23, 17, 10, 11, 6, 20, 9, 7, 11, 6, 11, 7, 24 (a) Represent the above data as a grouped data taking the class interval 15 < … chirban dr sharon aWebIn the formula x = a + h (fiui/fi), for finding the mean of grouped frequency distribution, ui = (A) (xi+a)/h (B) h (xi – a) (C) (xi –a)/h (D) (a – xi)/h Solution: (C) (xi –a)/h Explanation: According to the question, x = a + h (fiui/fi), Above formula is a step deviation formula. In the above formula, x i is data values, a is assumed mean, chirban dr sharon a ma - 02115